324=-16t^2+144t+0

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Solution for 324=-16t^2+144t+0 equation: 



324=-16t^2+144t+0

We move all terms to the left:

324-(-16t^2+144t+0)=0

We get rid of parentheses

16t^2-144t-0+324=0

We add all the numbers together, and all the variables

16t^2-144t+324=0

a = 16; b = -144; c = +324;
Δ = b2-4ac
Δ = -1442-4·16·324
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{144}{32}=4+1/2$

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